Help Java Array problem please help huhu

[Yaboku]

Hi can someone help me. Di ko madidisplay yung numbers. Yun nalang kulang huhu. Please help me

Heres my code:
import java.util.Scanner;

class Main {
public static void main(String[] args) {
int count;
int items = 5;
int newnum =0 ;
int highest=0;
int lowest =0;


Scanner input = new Scanner(System.in);


System.out.print("Input 5 numbers: ");

for (count=0; count<items; count++){
newnum= input.nextInt();

if (highest<newnum)
highest=newnum;

if (lowest==0)
lowest=newnum;

else if (newnum<=lowest)
lowest=newnum;

}

System.out.println("Highest value: "+highest);
System.out.println("Lowest Value: "+lowest);
}
}

 

[- Gray]

import java.util.Scanner;
import java.util.Arrays; 

class Main {
public static void main(String[] args) {
    
int items = 5;
int[] newnum = new int[5];
int highest=0;
int lowest =0;


Scanner input = new Scanner(System.in);

System.out.print("Input 5 numbers: ");

for (int i=0; i<items; i++){
newnum[i]= input.nextInt();

if (highest<newnum[i])
highest=newnum[i];

if (lowest==0)
lowest=newnum[i];

else if (newnum[i]<=lowest)
lowest=newnum[i];

}

System.out.println("Numbers: "+Arrays.toString(newnum)); 
System.out.println("Highest value: "+highest);
System.out.println("Lowest Value: "+lowest);

}
}

 

[zackmark29]

Try mo din to nirefactored ko lang ng kaunti since need mo lang max and min

import java.util.*;

public class Main
{
    public static void main(String[] args) {
        int count;
        int items = 5;
        int newnum = 0;
   
        Scanner input = new Scanner(System.in);
        System.out.print("Input 5 numbers: ");
       
        List<Integer> numbers = new ArrayList<>();
       
        for (count = 0; count < items; count++) {
            newnum = input.nextInt();
            numbers.add(newnum);
        }
        var highest = Collections.max(numbers);
        var lowest = Collections.min(numbers);
        System.out.println("Highest value: " + highest);
        System.out.println("Lowest Value: " + lowest);
    }
}

Input 5 numbers: 100
50
20
5
30
Highest value: 100
Lowest Value: 5

 

[Yaboku]

import java.util.Scanner;
import java.util.Arrays;

class Main {
public static void main(String[] args) {
   
int items = 5;
int[] newnum = new int[5];
int highest=0;
int lowest =0;


Scanner input = new Scanner(System.in);

System.out.print("Input 5 numbers: ");

for (int i=0; i<items; i++){
newnum[i]= input.nextInt();

if (highest<newnum[i])
highest=newnum[i];

if (lowest==0)
lowest=newnum[i];

else if (newnum[i]<=lowest)
lowest=newnum[i];

}

System.out.println("Numbers: "+Arrays.toString(newnum));
System.out.println("Highest value: "+highest);
System.out.println("Lowest Value: "+lowest);

}
}

check mo po TS beginner palang din ako ilang line lang ang dinadagdag ko sa code mo nag declare lang din ako ng array

Grabeh yun lang pala yun?

 

[- Gray]

Grabeh yun lang pala yun?

okay naman po sainyo?

 

[JHO113]

int count; int[] newNum = new int[5]; int highest = 0; int lowest = 0; Scanner input = new Scanner(System.in); System.out.print("Input 5 numbers: "); for (count = 0; count < newNum.length - 1; count++) { newNum[count] = input.nextInt(); if (highest < newNum[count]) highest = newNum[count]; if (lowest == 0) lowest = newNum[count]; else if (newNum[count] <= lowest) lowest = newNum[count]; } System.out.println("Highest value: " + highest); System.out.println("Lowest Value: " + lowest);
tested

 

[Yaboku]

okay naman po sainyo?

Lemme check kase may bracket siya sa numbers eh. Eh yung hiningi is walang bracket pero nadidisplay yung array ng inputs

 

[zackmark29]

Grabeh yun lang pala yun?

Yes haha para di na need mag compare inside the loop
Pero depende parin sa required ng prof niyo kung anong dapat gamitin for loop or etc..

 

[JHO113]

Arrays.stream(newNum).max().ifPresent(System.out:rintln);
Arrays.stream(newNum).min().ifPresent(System.out:rintln);
pwede din yan kaso mas advanced, shorter and readable, medyu mabigat ang streams pag madaming data

 

[Yaboku]

thank you po sa mga tips huhu

 

[JHO113]

explore mo data structures para d ka mahirapan, sa ngayon primitives muna tas non primitive na

may wrapper classes den for primitives, (Integer, Double) may methods dyan na makakatulong sayo

 

[zackmark29]

Ay yung output sa sample inline numbers.
Eto gamitin mo

import java.util.*;

public class Main
{
    public static void main(String[] args) {
        int count;
        int items = 5;
        int newnum = 0;
   
        Scanner input = new Scanner(System.in);
        System.out.print("Input 5 numbers: ");
       
        List<Integer> numbers = new ArrayList<>();
       
        // split the numbers separated by space
        for (String num : input.nextLine().split(" ")) {
            numbers.add(Integer.parseInt(num));
        }
       
        var highest = Collections.max(numbers);
        var lowest = Collections.min(numbers);
        System.out.println("Highest value: " + highest);
        System.out.println("Lowest Value: " + lowest);
    }
}

Input 5 numbers: 5 9 6 3 1
Highest value: 9
Lowest Value: 1

 

[Yaboku]

thank you po

 

[seorge24]

Ay yung output sa sample inline numbers.
Eto gamitin mo

import java.util.*;

public class Main
{
    public static void main(String[] args) {
        int count;
        int items = 5;
        int newnum = 0;
  
        Scanner input = new Scanner(System.in);
        System.out.print("Input 5 numbers: ");
      
        List<Integer> numbers = new ArrayList<>();
      
        // split the numbers separated by space
        for (String num : input.nextLine().split(" ")) {
            numbers.add(Integer.parseInt(num));
        }
      
        var highest = Collections.max(numbers);
        var lowest = Collections.min(numbers);
        System.out.println("Highest value: " + highest);
        System.out.println("Lowest Value: " + lowest);
    }
}

Input 5 numbers: 5 9 6 3 1
Highest value: 9
Lowest Value: 1

tama to, kasi nasunod yung requirement. pero I suggest since baguhan pa si OP, gawin nya muna yung pagcheck ng lowest saka highest value gamit yung if/else para masolidify muna yung basics.