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How many grams of ammonia are present in 5.0 L of a 0.050 M solution?

 

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To determine the number of grams of ammonia present in 5.0 L of a 0.050 M solution, you need to use the formula:

n = V x C

where n represents the number of moles of ammonia, V represents the volume of the solution in liters, and C represents the concentration of the solution in moles per liter.

First, let's calculate the number of moles of ammonia in 5.0 L of the solution:

n = V x C
n = 5.0 L x 0.050 mol/L
n = 0.25 mol

Next, we can use the molar mass of ammonia to convert the number of moles to grams:

m = n x M

where m represents the mass of ammonia in grams and M represents the molar mass of ammonia (17.03 g/mol).

m = n x M
m = 0.25 mol x 17.03 g/mol
m = 4.26 g

Therefore, there are 4.26 grams of ammonia in 5.0 L of a 0.050 M solution.