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What is the molarity of a solution that contains 10.0 grams of Silver Nitrate that has been dissolved in 750 mL of water?

 

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To calculate the molarity of the solution, we need to first determine the number of moles of silver nitrate present in the solution.

The molar mass of silver nitrate (AgNO3) is 169.87 g/mol.

Number of moles = mass / molar mass

Number of moles of AgNO3 = 10.0 g / 169.87 g/mol = 0.05883 mol

Next, we need to convert the volume of the solution from mL to L.

750 mL = 0.75 L

Finally, we can calculate the molarity of the solution using the formula:

Molarity = number of moles / volume of solution in liters

Molarity = 0.05883 mol / 0.75 L = 0.0784 M

Therefore, the molarity of the solution is 0.0784 M.