🤖 🤖 PHC Robot Oct 6, 2023 #2 To find the limit of sin(x) as x approaches 2π, we can use the fact that sin(x) is a continuous function. When x approaches 2π from the left side, sin(x) approaches 0 because sin(2π) = 0. Similarly, when x approaches 2π from the right side, sin(x) also approaches 0. Therefore, the limit of sin(x) as x approaches 2π is 0. Upvote 0 Downvote
To find the limit of sin(x) as x approaches 2π, we can use the fact that sin(x) is a continuous function. When x approaches 2π from the left side, sin(x) approaches 0 because sin(2π) = 0. Similarly, when x approaches 2π from the right side, sin(x) also approaches 0. Therefore, the limit of sin(x) as x approaches 2π is 0.
M Miwaa Eternal Poster Established Oct 6, 2023 TS TS #3 🤖 said: To find the limit of sin(x) as x approaches 2π, we can use the fact that sin(x) is a continuous function. When x approaches 2π from the left side, sin(x) approaches 0 because sin(2π) = 0. Similarly, when x approaches 2π from the right side, sin(x) also approaches 0. Therefore, the limit of sin(x) as x approaches 2π is 0. Click to expand... evaluate limx---3 4^x+5 Upvote 0 Downvote
🤖 said: To find the limit of sin(x) as x approaches 2π, we can use the fact that sin(x) is a continuous function. When x approaches 2π from the left side, sin(x) approaches 0 because sin(2π) = 0. Similarly, when x approaches 2π from the right side, sin(x) also approaches 0. Therefore, the limit of sin(x) as x approaches 2π is 0. Click to expand... evaluate limx---3 4^x+5
🤖 🤖 PHC Robot Oct 6, 2023 #4 Scopper Gaban said: evaluate limx---3 4^x+5 Click to expand... To evaluate the limit as x approaches 3 of 4^(x+5), we can substitute the value of x into the expression. When x approaches 3, we have: 4^(3+5) = 4^8 = 65,536 Therefore, the limit of 4^(x+5) as x approaches 3 is 65,536. Upvote 0 Downvote
Scopper Gaban said: evaluate limx---3 4^x+5 Click to expand... To evaluate the limit as x approaches 3 of 4^(x+5), we can substitute the value of x into the expression. When x approaches 3, we have: 4^(3+5) = 4^8 = 65,536 Therefore, the limit of 4^(x+5) as x approaches 3 is 65,536.
M Miwaa Eternal Poster Established Oct 6, 2023 TS TS #5 🤖 said: To evaluate the limit as x approaches 3 of 4^(x+5), we can substitute the value of x into the expression. When x approaches 3, we have: 4^(3+5) = 4^8 = 65,536 Therefore, the limit of 4^(x+5) as x approaches 3 is 65,536. Click to expand... no valuate limx---3 4^x+5 not 3 of 4^(x+5) Click to expand... Upvote 0 Downvote
🤖 said: To evaluate the limit as x approaches 3 of 4^(x+5), we can substitute the value of x into the expression. When x approaches 3, we have: 4^(3+5) = 4^8 = 65,536 Therefore, the limit of 4^(x+5) as x approaches 3 is 65,536. Click to expand... no valuate limx---3 4^x+5 not 3 of 4^(x+5) Click to expand...
🤖 🤖 PHC Robot Oct 6, 2023 #6 Scopper Gaban said: no valuate limx---3 4^x+5 not Click to expand... Apologies for the confusion. Let's reevaluate the limit. To evaluate the limit as x approaches 3 of 4^(x+5), we can rewrite it as 4^x * 4^5. As x approaches 3, 4^x approaches 4^3 = 64, and 4^5 = 1024. Hence, the limit of 4^(x+5) as x approaches 3 is 64 * 1024 = 65536. Upvote 0 Downvote
Scopper Gaban said: no valuate limx---3 4^x+5 not Click to expand... Apologies for the confusion. Let's reevaluate the limit. To evaluate the limit as x approaches 3 of 4^(x+5), we can rewrite it as 4^x * 4^5. As x approaches 3, 4^x approaches 4^3 = 64, and 4^5 = 1024. Hence, the limit of 4^(x+5) as x approaches 3 is 64 * 1024 = 65536.
M Miwaa Eternal Poster Established Oct 6, 2023 TS TS #7 🤖 said: Apologies for the confusion. Let's reevaluate the limit. To evaluate the limit as x approaches 3 of 4^(x+5), we can rewrite it as 4^x * 4^5. As x approaches 3, 4^x approaches 4^3 = 64, and 4^5 = 1024. Hence, the limit of 4^(x+5) as x approaches 3 is 64 * 1024 = 65536. Click to expand... EValuate limx---3 4^x + 5 Upvote 0 Downvote
🤖 said: Apologies for the confusion. Let's reevaluate the limit. To evaluate the limit as x approaches 3 of 4^(x+5), we can rewrite it as 4^x * 4^5. As x approaches 3, 4^x approaches 4^3 = 64, and 4^5 = 1024. Hence, the limit of 4^(x+5) as x approaches 3 is 64 * 1024 = 65536. Click to expand... EValuate limx---3 4^x + 5
🤖 🤖 PHC Robot Oct 6, 2023 #8 Scopper Gaban said: valuate limx---3 4^x + 5 Click to expand... I apologize for the confusion in my previous responses. It seems I misunderstood your expression. To evaluate the limit as x approaches 3 of 4^x + 5, we can substitute the value of x into the expression. When x approaches 3, we have: 4^3 + 5 = 64 + 5 = 69 Therefore, the limit of 4^x + 5 as x approaches 3 is 69. Upvote 0 Downvote
Scopper Gaban said: valuate limx---3 4^x + 5 Click to expand... I apologize for the confusion in my previous responses. It seems I misunderstood your expression. To evaluate the limit as x approaches 3 of 4^x + 5, we can substitute the value of x into the expression. When x approaches 3, we have: 4^3 + 5 = 64 + 5 = 69 Therefore, the limit of 4^x + 5 as x approaches 3 is 69.
M Miwaa Eternal Poster Established Oct 6, 2023 TS TS #9 🤖 said: I apologize for the confusion in my previous responses. It seems I misunderstood your expression. To evaluate the limit as x approaches 3 of 4^x + 5, we can substitute the value of x into the expression. When x approaches 3, we have: 4^3 + 5 = 64 + 5 = 69 Therefore, the limit of 4^x + 5 as x approaches 3 is 69. Click to expand... evaluate lim x---- -2 (2x+4)(x-5) Upvote 0 Downvote
🤖 said: I apologize for the confusion in my previous responses. It seems I misunderstood your expression. To evaluate the limit as x approaches 3 of 4^x + 5, we can substitute the value of x into the expression. When x approaches 3, we have: 4^3 + 5 = 64 + 5 = 69 Therefore, the limit of 4^x + 5 as x approaches 3 is 69. Click to expand... evaluate lim x---- -2 (2x+4)(x-5)
🤖 🤖 PHC Robot Oct 6, 2023 #10 Scopper Gaban said: evaluate lim x---- -2 (2x+4)(x-5) Click to expand... To evaluate the limit as x approaches -2 of -2(2x+4)(x-5), we can substitute the value of x into the expression. When x approaches -2, we have: -2(2(-2)+4)(-2-5) = -2(0)(-7) = 0 Therefore, the limit of -2(2x+4)(x-5) as x approaches -2 is 0. Upvote 0 Downvote
Scopper Gaban said: evaluate lim x---- -2 (2x+4)(x-5) Click to expand... To evaluate the limit as x approaches -2 of -2(2x+4)(x-5), we can substitute the value of x into the expression. When x approaches -2, we have: -2(2(-2)+4)(-2-5) = -2(0)(-7) = 0 Therefore, the limit of -2(2x+4)(x-5) as x approaches -2 is 0.
M Miwaa Eternal Poster Established Oct 6, 2023 TS TS #11 🤖 said: To evaluate the limit as x approaches -2 of -2(2x+4)(x-5), we can substitute the value of x into the expression. When x approaches -2, we have: -2(2(-2)+4)(-2-5) = -2(0)(-7) = 0 Therefore, the limit of -2(2x+4)(x-5) as x approaches -2 is 0. Click to expand... evaluate limx---3 (x^2 +x-12/x-3) Upvote 0 Downvote
🤖 said: To evaluate the limit as x approaches -2 of -2(2x+4)(x-5), we can substitute the value of x into the expression. When x approaches -2, we have: -2(2(-2)+4)(-2-5) = -2(0)(-7) = 0 Therefore, the limit of -2(2x+4)(x-5) as x approaches -2 is 0. Click to expand... evaluate limx---3 (x^2 +x-12/x-3)