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[MINDBLOWN]

Patulong boss. Thanks in advance.

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[bakasta]

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[MINDBLOWN]

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[Catubig03]

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[MINDBLOWN]

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Solution:

Reorder point =12

Subtotal = Par stock - Reorder Point = 42 - 12 = 30

Reorder quantity = Subtotal + Normal Usage = 30 + 21 = 51

Thus, reorder point is 12 and reorder quantity is 51.

 

[Catubig03]

Solution:

Reorder point =12

Subtotal = Par stock - Reorder Point = 42 - 12 = 30

Reorder quantity = Subtotal + Normal Usage = 30 + 21 = 51

Thus, reorder point is 12 and reorder quantity is 51.

Salamat po ng marami

 

[Regg]

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pa help po salamat!

 

[MINDBLOWN]

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Sol :-

Use the steps :

Step.1 :- Balance the oxidation and reduction half cell reactions separately.

Step.2 :- Balance the atoms other than hydrogen and oxygen first.

Step.3 :- Balance the O atom by adding suitable number of H2O.

Step.4 :- Balance the hydrogen atom by adding suitable number of H+ .

Step.5 :- Balance the charge on both side by adding suitable number of electrons.

(a). Oxidation half cell reaction is :

VO2+ + 3H2O ------------> V(OH)4+ + 2H+ + 1e-

Reduction half cell reaction is :

MnO4- + 8H+ + 5e-------------> Mn2+ + 4H2O

Multiply oxidation half by 5 and then add both half cells, So

Balanced redox reaction in acidic medium is :

MnO4- + 5VO2+ + 11H2O ------------> Mn2+ + 5V(OH)4+ + 2H+

Oxidizing agent = MnO4-

and

Reducing agent = VO2+

(b).

Oxidation half cell reaction is :

H2S ------------> S + 2H+ + 2e-

Reduction half cell reaction is :

I2 + 2e- ------------> 2I-

Add both half cells, So

Balanced redox reaction in acidic medium is :

I2 + H2S ------------> 2I- + S + 2H+

Oxidizing agent = I2

and

Reducing agent = H2S

(c).

Oxidation half cell reaction is :

U4+ + 2H2O ------------> UO22+ + 4H+ + 2e-

Reduction half cell reaction is :

Cr2O72- + 14H+ + 6e- ------------> 2Cr3+ + 7H2O

Multiply oxidation half by 3 and then add both half cells, So

Balanced redox reaction in acidic medium is :

Cr2O72- + 2H+ + 3U4+ ------> 2Cr3+ + 3UO22+ + H2O

Oxidizing agent = Cr2O72-

and

Reducing agent = U4+

(d).

Oxidation half cell reaction is :

2Cl- -------------> Cl2 + 2e-

Reduction half cell reaction is :

MnO2 + 4H+ + 2e- -------------> Mn2+ + 2H2O

Add both half cells, So

Balanced redox reaction in acidic medium is :

2Cl- + MnO2 + 4H+ ------------> Cl2 + Mn2+ + 2H2O

Oxidizing agent = MnO2

and

Reducing agent = Cl-

(g).

Oxidation half cell reaction is :

HPO32- + H2O -------------> PO43- + 3H+ + 2e-

Reduction half cell reaction is :

MnO4- + 1e- -------------> MnO42-

Multiply reduction half by 2 and then add both half cells, So

Balanced redox reaction in acidic medium is :

HPO32- + 2MnO4- + H2O -----------> PO43- + 2MnO42- + 3H+

Add 3OH- on both the sides, So

Balanced redox reaction in basic medium is :

HPO32- + 2MnO4- + 3OH- -----------> PO43- + 2MnO42- + 2H2O

Oxidizing agent = MnO4-

and

Reducing agent = HPO32-

 

[Regg]

Sol :-

Use the steps :

Step.1 :- Balance the oxidation and reduction half cell reactions separately.

Step.2 :- Balance the atoms other than hydrogen and oxygen first.

Step.3 :- Balance the O atom by adding suitable number of H2O.

Step.4 :- Balance the hydrogen atom by adding suitable number of H+ .

Step.5 :- Balance the charge on both side by adding suitable number of electrons.

(a). Oxidation half cell reaction is :

VO2+ + 3H2O ------------> V(OH)4+ + 2H+ + 1e-

Reduction half cell reaction is :

MnO4- + 8H+ + 5e-------------> Mn2+ + 4H2O

Multiply oxidation half by 5 and then add both half cells, So

Balanced redox reaction in acidic medium is :

MnO4- + 5VO2+ + 11H2O ------------> Mn2+ + 5V(OH)4+ + 2H+

Oxidizing agent = MnO4-

and

Reducing agent = VO2+

(b).

Oxidation half cell reaction is :

H2S ------------> S + 2H+ + 2e-

Reduction half cell reaction is :

I2 + 2e- ------------> 2I-

Add both half cells, So

Balanced redox reaction in acidic medium is :

I2 + H2S ------------> 2I- + S + 2H+

Oxidizing agent = I2

and

Reducing agent = H2S

(c).

Oxidation half cell reaction is :

U4+ + 2H2O ------------> UO22+ + 4H+ + 2e-

Reduction half cell reaction is :

Cr2O72- + 14H+ + 6e- ------------> 2Cr3+ + 7H2O

Multiply oxidation half by 3 and then add both half cells, So

Balanced redox reaction in acidic medium is :

Cr2O72- + 2H+ + 3U4+ ------> 2Cr3+ + 3UO22+ + H2O

Oxidizing agent = Cr2O72-

and

Reducing agent = U4+

(d).

Oxidation half cell reaction is :

2Cl- -------------> Cl2 + 2e-

Reduction half cell reaction is :

MnO2 + 4H+ + 2e- -------------> Mn2+ + 2H2O

Add both half cells, So

Balanced redox reaction in acidic medium is :

2Cl- + MnO2 + 4H+ ------------> Cl2 + Mn2+ + 2H2O

Oxidizing agent = MnO2

and

Reducing agent = Cl-

(g).

Oxidation half cell reaction is :

HPO32- + H2O -------------> PO43- + 3H+ + 2e-

Reduction half cell reaction is :

MnO4- + 1e- -------------> MnO42-

Multiply reduction half by 2 and then add both half cells, So

Balanced redox reaction in acidic medium is :

HPO32- + 2MnO4- + H2O -----------> PO43- + 2MnO42- + 3H+

Add 3OH- on both the sides, So

Balanced redox reaction in basic medium is :

HPO32- + 2MnO4- + 3OH- -----------> PO43- + 2MnO42- + 2H2O

Oxidizing agent = MnO4-

and

Reducing agent = HPO32-

salamat po!

 

[Lokats]

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[MINDBLOWN]

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4) Acute pain related to abdominal mass as evidenced by pain score.

6) In checklist we have to mention medication received pre-operative wth dose and time of administration.

7) as atropine is give watch fr heart rate

8)International patient goal are: identification of pt ( by name band and asking pts his name )

-Improve effective communication

-Improve the safety of HR medication

-Ensure safe surgery

-Reduce hospital acquired infection

SURGICAL SAFETY CHECKLIST:

Ward staff ll shift the pt to recovery room where the recovery nurse ll indentifu pt by his band and confirming him by asking his name, consultant name and sx plannef for him, from when he is nbm, did sx siye marking is there or nt. Then technician , circulatory nurse ll take the pt to ot room . There circultory nurse ll again ask the pt name , age ,cinsultant name and sx bame planned for . Anesthetic ll do the same . time in ,timeout n sign out time ll be mention.

PACU NURSE :9) should watch for is pt is drowsy, pain, after he is awake .

10)oxygenation requirement as pt has h/o copd no oxygen is give insted we can give air by neb mask or face mask.

11)SURGEON NEED TO KNOW:

- his vitals

-drain output

Urine output

Oozing from surgical site

12) sacrum, heels ,elbow

13) monitor glucose,saturation, drain output , mobilzation, administration of pain medication.

14) pt is responsible fr his recovery by following nurses request n instead of pain he does early mobilization, taking medicine and taking rest as well.

15) pt need emotinal support. provide psychological support by encouraging him giving postive attitude comfort.

17) we ll inform to junior consultant about the drain and if says to change we ll go ahead if no so can't do anything.

18) When did pts had his last meal we need to check it first . and after doing the procedure nt to attached on suction port again

19) IS ll expand the lung n facilitate the breathing.

20) hemorrage as pt undergone for sx surgical site is at risk till it heal .

Abdominal distention bcz of sx pt may have pain while passing stool so it can happen

 

[Lokats]

4) Acute pain related to abdominal mass as evidenced by pain score.

6) In checklist we have to mention medication received pre-operative wth dose and time of administration.

7) as atropine is give watch fr heart rate

8)International patient goal are: identification of pt ( by name band and asking pts his name )

-Improve effective communication

-Improve the safety of HR medication

-Ensure safe surgery

-Reduce hospital acquired infection

SURGICAL SAFETY CHECKLIST:

Ward staff ll shift the pt to recovery room where the recovery nurse ll indentifu pt by his band and confirming him by asking his name, consultant name and sx plannef for him, from when he is nbm, did sx siye marking is there or nt. Then technician , circulatory nurse ll take the pt to ot room . There circultory nurse ll again ask the pt name , age ,cinsultant name and sx bame planned for . Anesthetic ll do the same . time in ,timeout n sign out time ll be mention.

PACU NURSE :9) should watch for is pt is drowsy, pain, after he is awake .

10)oxygenation requirement as pt has h/o copd no oxygen is give insted we can give air by neb mask or face mask.

11)SURGEON NEED TO KNOW:

- his vitals

-drain output

Urine output

Oozing from surgical site

12) sacrum, heels ,elbow

13) monitor glucose,saturation, drain output , mobilzation, administration of pain medication.

14) pt is responsible fr his recovery by following nurses request n instead of pain he does early mobilization, taking medicine and taking rest as well.

15) pt need emotinal support. provide psychological support by encouraging him giving postive attitude comfort.

17) we ll inform to junior consultant about the drain and if says to change we ll go ahead if no so can't do anything.

18) When did pts had his last meal we need to check it first . and after doing the procedure nt to attached on suction port again

19) IS ll expand the lung n facilitate the breathing.

20) hemorrage as pt undergone for sx surgical site is at risk till it heal .

Abdominal distention bcz of sx pt may have pain while passing stool so it can happen

Salamat ng marami boss Godbless po

 

[Deleted member 1872347]

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[MINDBLOWN]

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1st link :
What is the molar solubility of PbCl2 in a solution containing 0.020 M Cl-(aq)? The Ksp for PbCl2 is 1.6x10-5 ?

ksp(PbCl2)=Pb2+ + 2Cl1-

ksp=[Pb2+][Cl1-]2

solubility in pure water

ksp=s*(2s)2=4s3

s=(ksp/4)0.333=(1.6/4x10-5)0.333=0.01594moles/L

now solubility of lead chloride containing 0.02M Cl1- ions is as

Pb2+=ksp/[Cl1-]2=(1.6x10-5)/(0.02)2=0.04M
2nd link:

3rd link:

4th link:
Answer (16)

(C) 3

Answer (17)

t-butoxide can be used to form the “less substituted” alkenes in elimination reactions (the E2, specifically).

(d) KOtBu

Answer (18)

Stability of Radicals. Due to the unpaired electrons, free radicals do not have an electron octet. Therefore, they are usually instable and highly reactive. As a result of their high reactivity, radicals merely show a low selectivity.

(C) 2 > 3 > 1
5th link:

 

[Deleted member 1872347]

1st link :
What is the molar solubility of PbCl2 in a solution containing 0.020 M Cl-(aq)? The Ksp for PbCl2 is 1.6x10-5 ?

ksp(PbCl2)=Pb2+ + 2Cl1-

ksp=[Pb2+][Cl1-]2

solubility in pure water

ksp=s*(2s)2=4s3

s=(ksp/4)0.333=(1.6/4x10-5)0.333=0.01594moles/L

now solubility of lead chloride containing 0.02M Cl1- ions is as

Pb2+=ksp/[Cl1-]2=(1.6x10-5)/(0.02)2=0.04M
2nd link:
View attachment 1513843
3rd link:
View attachment 1513844
4th link:
Answer (16)

(C) 3

Answer (17)

t-butoxide can be used to form the “less substituted” alkenes in elimination reactions (the E2, specifically).

(d) KOtBu

Answer (18)

Stability of Radicals. Due to the unpaired electrons, free radicals do not have an electron octet. Therefore, they are usually instable and highly reactive. As a result of their high reactivity, radicals merely show a low selectivity.

(C) 2 > 3 > 1
5th link:
View attachment 1513845

Thank you!

 

[Jayem08]

Paps pa unlock po...salamat
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[Deleted member 1872347]

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[Sim Sim]

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Pahelp po ulit. Thankssss

 

[MINDBLOWN]

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1:
Structure d is most activated towards electrophilic aromatic stubstitution reaction, because OH and OMe are ring ac†ïvâ†ørs.

Structure a is least activated toward electrophilic aromatic substitution reaction,because NO2 is a strong ring deac†ïvâ†ør compared to bromine.
2.

3.
A noble gas has completely filled up electronic configuration. Thus , it needs very high energy to remove one electron from this stable state. So. noble gas has very high Ionization energy. Here, Argon, (Ar) will top the list.

Then , according to the periodic trend, from left to right according to a periodic table, the Ionization energy increases. So, The trend for 3rd period will be , Na<P<Cl. Also , Li being element of 2nd period , the Ionization energy - Na<Li.

Combining all, the trend will be-

Na<Li<P<Cl<Ar
4.

5.

Correct answer is 1

The reaction goes in SN2 mechanism

-Br is good leaving group

-CH3SH is nucleophile

CH3SH Will attack on bromo and product will form

Mechanism is in two step

partial attack of nucleophile and partial leaving group removed is the transition state

Rate of reaction will depend on both nucleophile (CH3SH) and leaving group (Br)

Stereochemistry

There is no any Chiral carbon in the reaction so no stereochemistry will be there.

Please find attached file for reaction

 

[MINDBLOWN]

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Pahelp po ulit. Thankssss