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Pa mark as solution nalang lods

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AY (414) re= (y-2)² y=n (til) n - y = - L fig: Rough Sketch of bounded region. For intersection points y = (y-2)² = y²-54 +4=
du ta 4 J (8 nu - 125 4 4 4 udn. + + s Sdn - 125/2n 3 } + 6 V =* | C3 +- +5w3-(3-5 w.) ²] ax S&+sw.)? (metallo Studeni w² +65



 

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