To solve these questions, we can use the concept of an arithmetic series. In an arithmetic series, each term is obtained by adding a constant difference to the previous term.
Let's find the values for each question:
A. How much money will he have after 30 days?
To find the total amount of money after 30 days, we can use the formula for the sum of an arithmetic series:
Sn = (n/2) * (2a + (n-1)d)
Where:
Sn = sum of the series
n = number of terms
a = first term
d = common difference
In this case, the first term (a) is 10 pesos, the common difference (d) is 3 pesos, and the number of terms
is 30 (since he saves money for 30 days).
Using the formula:
S30 = (30/2) * (2*10 + (30-1)*3)
= 15 * (20 + 29*3)
= 15 * (20 + 87)
= 15 * 107
= 1,605 pesos
Therefore, Junior will have 1,605 pesos after 30 days.
B. How much money did he put in his piggy bank on the 3rd day after today?
To find the amount of money on the 3rd day, we can use the formula for the nth term of an arithmetic series:
an = a + (n-1)d
Where:
an = nth term
a = first term
d = common difference
In this case, the first term (a) is 10 pesos, the common difference (d) is 3 pesos, and the value of n is 3 (since we are interested in the 3rd day).
Using the formula:
a3 = 10 + (3-1)*3
= 10 + 2*3
= 10 + 6
= 16 pesos
Therefore, Junior put 16 pesos in his piggy bank on the 3rd day after today.
C. After how many days did he reach a total savings of 2,250 pesos?
To find the number of days required to reach a total savings of 2,250 pesos, we need to rearrange the formula for the sum of an arithmetic series:
Sn = (n/2) * (2a + (n-1)d)
In this case, the first term (a) is 10 pesos, the common difference (d) is 3 pesos, and the sum (Sn) is 2,250 pesos.
We can rewrite the formula as a quadratic equation: n^2 + 29n - 450 = 0
Solving this equation, we find that n = 15 or n = -30. Since the number of days cannot be negative, the answer is 15.
Therefore, Junior reached a total savings of 2,250 pesos after 15 days.