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We first note that both As2O3 and Mg2As2O7 contain two arsenic atoms, so we will not need a ny extra conversion in the calculations.
310.4490 g Mg2As2O7 = 1 mol
0.1065 g of Mg2As2O7 = 0.000343 moles

(2) 1 mole As2O3 is equivalent to 1 mole of Mg2As2O7 (as stated above, each contains 2 moles of arsenic), so

0.000343 moles Mg2As2O7.= 0.000343 moles As2O3.
197.8 g As2O3 means one mole

0.000343 moles means =0.000343 x 197.8=0.0678454grmns


(4) calculate % As2O3 in sample:

% As2O3 = 100% x (0.0678485_ g As2O3)/(1.627-g sample of insecticide) = __4.17 % As2O3
 
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[XX='makerkent, c: 1282507, m: 754230'][/XX] oo nga lods eh ang haba ng mga solutions 😅 pero maraming salamat lodiii sa walang sawang pagtulong samin. Godbless you po lagi😊
 
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