Reviewer Coursehero- Twice Unlocking - Services

[Lopyy-chann]

Bossing, pa unlock po neto, needed ko lang sa thesis

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Salamat po sa inyo

Here is your unlock PHC - Ivhan
Pasensya na po sa pag hahantay.
Stay safe po ^^

 

[rakhistha]

pa unlock naman po..salamat po..

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[Lopyy-chann]

pa unlock naman po..salamat po..

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Here is your unlock rakhistha

Stay safe po ^^

 

[rakhistha]

Maraming salamat po..

 

[PHC - Cat]

Pa unlock po ts, for our capstone project

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[asdkill]

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Paunlock po maraming salamat po sobra

 

[Adeptus03]

Makikiunlock naman po idol Lopyy-chann. Thank you in advance at God bless.

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[Lopyy-chann]

Pa unlock po ts, for our capstone project

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Here is your unlock PHC - Cat

Stay safe po ^^

 

[Lopyy-chann]

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Paunlock po maraming salamat po sobra

Here is your unlock asdkill

Stay safe po ^^

 

[Lopyy-chann]

Makikiunlock naman po idol Lopyy-chann. Thank you in advance at God bless.

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Here is your unlock markjeric54

Stay safe po ^^

 

[asdkill]

Here is your unlock asdkill

Stay safe po ^^

Sobrang thank you po blessing po kayo

 

[Adeptus03]

Here is your unlock markjeric54

Stay safe po ^^

Salamat po ng madami idol Lopyy-chann. Keep safe and God bless.

 

[Lopyy-chann]

I appreciated your feedback ^^

 

[Lopyy-chann]

Welcome and God bless din po sa inyo ^^

 

[I am nobody]

Lopyy-chann pa unlock po lods

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[Lopyy-chann]

Lopyy-chann pa unlock po lods

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Here is your unlock Rafleshia

Stay safe po ^^

 

[I am nobody]

Salamat po Lopyy-chann

 

[BototoyTheGreat24]

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Sana mapansin ts. Salamat!

 

[Lopyy-chann]

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Sana mapansin ts. Salamat!

Here is you unlock BototoyTheGreat24

Stay safe po^^

Answer & Explanation

Solution= solvent+ solute

Solute: The substance which is present in lesser amounts in the solution

Solvent: The substance which is present in higher amounts in the solution.

Step-by-step explanation

Image transcription text

Molarity = number of moles of the solute Volume of the solution in Litres Solute: The compound which is present in lesser amount the solution. Solvent: The compound which is present in higher amount in the solution. Solution = solute + solvent Molarity = number of moles of Ally Volume of the solution in Litres. 1 1 = 10 md 1ml = 10 L humber of moles of = Molarity x volume of the solution in All3 Litres 0. 85 M X 1250 X 10 L = 1. 0625 moles

Image transcription text

Molar mass of Alchy = 133.34 9 mol mass of ALug = humber of moles of X molar mass of All Alus 2 (1 - 06 25 mol ) X 133 . 34 9 = 141.673759 mass of Adds required = 141.673759 K ,soy - 2 k+ + soy Oxidation state of soy is ( - 2 ) n factor is '2' Molarity = Normality n - factor Molarity = 9.25 M Molarity = 4.625 M

Image transcription text

Number of moles of = Molarity x volume of the solution in K, soy Litres 4-625 M X 0.5L 2.3125 moles mass of K, soy = moles of K, soy x Molar mass of K, soy 2.3125 mod x 174. 259 9 mol = 402 . 9739 3759 ( " ) % = mass of the solute X 100 mass of the solution Here solute is ca(OH),. mass of (a (OH ), 13-2 = X loo 3509 mass of ca (OH), = 13 . 2X 350 loo mass of ca (OH), = 46.20 9.

Image transcription text

(2) mass of the solute ing' X 100 volume of the solution in me ( * ) = mass of CH2OH X loo volume of the Solution in me 22 X 100 100 ( w 1 % = 22 %%. Volume of the solute in and X loo Volume of the solution in md Here the solute is CH, OH Volume of CH3OH X loo Volume of the solution in and ( ) : = lomd X loo = 25%% yo ml

 

[PHC-klrst]

lodicakes pa unlock naman nito oh. Thanks in advance!

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