D Deng- Addict Joined Feb 27, 2018 Posts 134 Reaction 29 Points 112 Age 25 Jun 14, 2022 #1 Pa sagot naman nito mga lods The fifth number plus the first number equals sixteen. The sum of twice the second number plus 1 equals the fifth number. The fourth number is one more than the second number. The first number is one less than twice the second number. The second number plus the third number equals ten. The sum of all five numbers is 31.
Pa sagot naman nito mga lods The fifth number plus the first number equals sixteen. The sum of twice the second number plus 1 equals the fifth number. The fourth number is one more than the second number. The first number is one less than twice the second number. The second number plus the third number equals ten. The sum of all five numbers is 31.
C conviction Forum Guru Jun 14, 2022 #2 The fifth number plus the first number equals sixteen. The sum of twice the second number plus 1 equals the fifth number. The fourth number is one more than the second number. The first number is one less than twice the second number. The second number plus the third number equals ten. The sum of all five numbers is 31. let a+b+c+d+e=31 e+a=16 e=2b+1 d=b+1 a=2b-1 b+c=10 or c=10-b solve for b first substitute in a+b+c+d+e=31 (2b-1) + b + (10-b) + (b+1) + (2b+1) = 31 5b=31-11 b=4 sub b in a,c,d,e a=7 c=6 d=5 e=9
The fifth number plus the first number equals sixteen. The sum of twice the second number plus 1 equals the fifth number. The fourth number is one more than the second number. The first number is one less than twice the second number. The second number plus the third number equals ten. The sum of all five numbers is 31. let a+b+c+d+e=31 e+a=16 e=2b+1 d=b+1 a=2b-1 b+c=10 or c=10-b solve for b first substitute in a+b+c+d+e=31 (2b-1) + b + (10-b) + (b+1) + (2b+1) = 31 5b=31-11 b=4 sub b in a,c,d,e a=7 c=6 d=5 e=9
D Deng- Addict Jun 15, 2022 TS TS #3 PHC-Ethos said: The fifth number plus the first number equals sixteen. The sum of twice the second number plus 1 equals the fifth number. The fourth number is one more than the second number. The first number is one less than twice the second number. The second number plus the third number equals ten. The sum of all five numbers is 31. let a+b+c+d+e=31 e+a=16 e=2b+1 d=b+1 a=2b-1 b+c=10 or c=10-b solve for b first substitute in a+b+c+d+e=31 (2b-1) + b + (10-b) + (b+1) + (2b+1) = 31 5b=31-11 b=4 sub b in a,c,d,e a=7 c=6 d=5 e=9 Click to expand... Thank you lods
PHC-Ethos said: The fifth number plus the first number equals sixteen. The sum of twice the second number plus 1 equals the fifth number. The fourth number is one more than the second number. The first number is one less than twice the second number. The second number plus the third number equals ten. The sum of all five numbers is 31. let a+b+c+d+e=31 e+a=16 e=2b+1 d=b+1 a=2b-1 b+c=10 or c=10-b solve for b first substitute in a+b+c+d+e=31 (2b-1) + b + (10-b) + (b+1) + (2b+1) = 31 5b=31-11 b=4 sub b in a,c,d,e a=7 c=6 d=5 e=9 Click to expand... Thank you lods