L Lmr123 Eternal Poster Established Joined Dec 13, 2020 Posts 560 Reaction 1,556 Points 501 Nov 11, 2022 #1 Find the volume of the solid revolution generated by the curves y=x2 and the line x=3 and the x-axis y revolving around the line x=-3 asap
Find the volume of the solid revolution generated by the curves y=x2 and the line x=3 and the x-axis y revolving around the line x=-3 asap
P PHC- Naksu Forum Expert Elite Nov 11, 2022 #2 Try lang lods Intersection point of the two curves are by solving the two equations together as (-2,5) and (1,2) Volume generated about x axis is∫πy^2 dx for each curve and by difference for region in between =∫π(x^2+1)^2 dx- ∫π(-x+3)^2 dx range of x= -2 to 1 =π∫(x^4+2x^2+1)dx-π∫(x^2-6x+9)dx =π(x^5/5+2x^3/3+x-(x^3/3-6x^2/2+9x) range of x= -2 to 1 =π(x^5/5+x^3/3+3x^2-8x) range of x= -2 to 1 =π((-2)^5/5+(-2)^3/3+3(-2)^2-8(-2))- (((1)^5/5+(1)^3/3+3(1)^2-8(1)) =π((-32/5-8/3+12+16)-((1/5+1/3+3-8)) =π(-33/5+30) =π(117/5) =23.4π
Try lang lods Intersection point of the two curves are by solving the two equations together as (-2,5) and (1,2) Volume generated about x axis is∫πy^2 dx for each curve and by difference for region in between =∫π(x^2+1)^2 dx- ∫π(-x+3)^2 dx range of x= -2 to 1 =π∫(x^4+2x^2+1)dx-π∫(x^2-6x+9)dx =π(x^5/5+2x^3/3+x-(x^3/3-6x^2/2+9x) range of x= -2 to 1 =π(x^5/5+x^3/3+3x^2-8x) range of x= -2 to 1 =π((-2)^5/5+(-2)^3/3+3(-2)^2-8(-2))- (((1)^5/5+(1)^3/3+3(1)^2-8(1)) =π((-32/5-8/3+12+16)-((1/5+1/3+3-8)) =π(-33/5+30) =π(117/5) =23.4π
L Lmr123 Eternal Poster Established Nov 11, 2022 TS TS #3 neolicious45 said: Try lang lods Intersection point of the two curves are by solving the two equations together as (-2,5) and (1,2) Volume generated about x axis is∫πy^2 dx for each curve and by difference for region in between =∫π(x^2+1)^2 dx- ∫π(-x+3)^2 dx range of x= -2 to 1 =π∫(x^4+2x^2+1)dx-π∫(x^2-6x+9)dx =π(x^5/5+2x^3/3+x-(x^3/3-6x^2/2+9x) range of x= -2 to 1 =π(x^5/5+x^3/3+3x^2-8x) range of x= -2 to 1 =π((-2)^5/5+(-2)^3/3+3(-2)^2-8(-2))- (((1)^5/5+(1)^3/3+3(1)^2-8(1)) =π((-32/5-8/3+12+16)-((1/5+1/3+3-8)) =π(-33/5+30) =π(117/5) =23.4π Click to expand... sure na to lods? sasagot ko na to HAHAHAHHA
neolicious45 said: Try lang lods Intersection point of the two curves are by solving the two equations together as (-2,5) and (1,2) Volume generated about x axis is∫πy^2 dx for each curve and by difference for region in between =∫π(x^2+1)^2 dx- ∫π(-x+3)^2 dx range of x= -2 to 1 =π∫(x^4+2x^2+1)dx-π∫(x^2-6x+9)dx =π(x^5/5+2x^3/3+x-(x^3/3-6x^2/2+9x) range of x= -2 to 1 =π(x^5/5+x^3/3+3x^2-8x) range of x= -2 to 1 =π((-2)^5/5+(-2)^3/3+3(-2)^2-8(-2))- (((1)^5/5+(1)^3/3+3(1)^2-8(1)) =π((-32/5-8/3+12+16)-((1/5+1/3+3-8)) =π(-33/5+30) =π(117/5) =23.4π Click to expand... sure na to lods? sasagot ko na to HAHAHAHHA
W WiggLeZ_101 Forum Veteran Nov 11, 2022 #4 Lmr123 said: sure na to lods? sasagot ko na to HAHAHAHHA Click to expand... sure nayan sagot muna dali
Lmr123 said: sure na to lods? sasagot ko na to HAHAHAHHA Click to expand... sure nayan sagot muna dali
P PHC- Naksu Forum Expert Elite Nov 11, 2022 #5 Lmr123 said: sure na to lods? sasagot ko na to HAHAHAHHA Click to expand... sabi ko nga try lang eh hehehe if d mo naintindihan ung sinagot ko wag mo n isulat dhil d mo rin nman maipapaliwanag
Lmr123 said: sure na to lods? sasagot ko na to HAHAHAHHA Click to expand... sabi ko nga try lang eh hehehe if d mo naintindihan ung sinagot ko wag mo n isulat dhil d mo rin nman maipapaliwanag
L Lmr123 Eternal Poster Established Nov 11, 2022 TS TS #7 Queen Buns said: Wala ka ng no choice kaya isulat mo na Click to expand... neolicious45 said: sabi ko nga try lang eh hehehe if d mo naintindihan ung sinagot ko wag mo n isulat dhil d mo rin nman maipapaliwanag Click to expand... WiggLeZ_101 said: sure nayan sagot muna dali Click to expand... sasagot ko na, salamat sa inyo guys balitaan ko kayo kung ano score ko HAHAHAHHA
Queen Buns said: Wala ka ng no choice kaya isulat mo na Click to expand... neolicious45 said: sabi ko nga try lang eh hehehe if d mo naintindihan ung sinagot ko wag mo n isulat dhil d mo rin nman maipapaliwanag Click to expand... WiggLeZ_101 said: sure nayan sagot muna dali Click to expand... sasagot ko na, salamat sa inyo guys balitaan ko kayo kung ano score ko HAHAHAHHA
P PHC- Naksu Forum Expert Elite Nov 11, 2022 #8 Lmr123 said: sasagot ko na, salamat sa inyo guys balitaan ko kayo kung ano score ko HAHAHAHHA Click to expand... cge goodluck lods kaya mong ipasa yan n nkatakip ang isang mata hehe
Lmr123 said: sasagot ko na, salamat sa inyo guys balitaan ko kayo kung ano score ko HAHAHAHHA Click to expand... cge goodluck lods kaya mong ipasa yan n nkatakip ang isang mata hehe
L Lmr123 Eternal Poster Established Nov 11, 2022 TS TS #9 neolicious45 said: cge goodluck lods kaya mong ipasa yan n nkatakip ang isang mata hehe Click to expand... ayan ang sound :>
neolicious45 said: cge goodluck lods kaya mong ipasa yan n nkatakip ang isang mata hehe Click to expand... ayan ang sound :>