evaluate limx---3 4^x+5To find the limit of sin(x) as x approaches 2π, we can use the fact that sin(x) is a continuous function.
When x approaches 2π from the left side, sin(x) approaches 0 because sin(2π) = 0.
Similarly, when x approaches 2π from the right side, sin(x) also approaches 0.
Therefore, the limit of sin(x) as x approaches 2π is 0.
To evaluate the limit as x approaches 3 of 4^(x+5), we can substitute the value of x into the expression.evaluate limx---3 4^x+5
noTo evaluate the limit as x approaches 3 of 4^(x+5), we can substitute the value of x into the expression.
When x approaches 3, we have:
4^(3+5) = 4^8 = 65,536
Therefore, the limit of 4^(x+5) as x approaches 3 is 65,536.
3 of 4^(x+5)
Apologies for the confusion. Let's reevaluate the limit.no
valuate limx---3 4^x+5 not
EValuate limx---3 4^x + 5Apologies for the confusion. Let's reevaluate the limit.
To evaluate the limit as x approaches 3 of 4^(x+5), we can rewrite it as 4^x * 4^5.
As x approaches 3, 4^x approaches 4^3 = 64, and 4^5 = 1024.
Hence, the limit of 4^(x+5) as x approaches 3 is 64 * 1024 = 65536.
I apologize for the confusion in my previous responses. It seems I misunderstood your expression.valuate limx---3 4^x + 5
evaluate lim x---- -2 (2x+4)(x-5)I apologize for the confusion in my previous responses. It seems I misunderstood your expression.
To evaluate the limit as x approaches 3 of 4^x + 5, we can substitute the value of x into the expression.
When x approaches 3, we have:
4^3 + 5 = 64 + 5 = 69
Therefore, the limit of 4^x + 5 as x approaches 3 is 69.
To evaluate the limit as x approaches -2 of -2(2x+4)(x-5), we can substitute the value of x into the expression.evaluate lim x---- -2 (2x+4)(x-5)
evaluate limx---3 (x^2 +x-12/x-3)To evaluate the limit as x approaches -2 of -2(2x+4)(x-5), we can substitute the value of x into the expression.
When x approaches -2, we have:
-2(2(-2)+4)(-2-5)
= -2(0)(-7)
= 0
Therefore, the limit of -2(2x+4)(x-5) as x approaches -2 is 0.