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[Unkown User]

Drop LInks mga idol
CHEGG LINKS

Close ko din agad kapag busy na uli.

 

[Escanor]

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kaya ba lods dalawa hehe salamat po

 

[markdieltiao]

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[Unkown User]

I.

II.

 

[Unkown User]

Question: The anchor bolt was pulled out of the concrete wall and the failure surface formed part of a frus...​

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[Unkown User]

[XX='Elo Max, c: 1264388, m: 871424'][/XX]

 

[Nur54]

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[Nur54]

Master patulong dito hindi ko talaga masagutan

 

[Slime-]

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[Unkown User]

Question: 7. A different mode. The kinetics of the enzyme considered in problem 6 are measured in the prese...​

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PLEASE SHOW ME HOW TO CALCULATE STEP BY STEP QUESTION A.
THANK-YOU
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  Anonymousanswered this
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  Lineweaver-burk plot will be used to determine the constants. The equation is
  1/V= (KM/Vmax)*1/S + 1/Vmax
  So a plot of 1/V vs 1/S gives straight line whose slope is KM/Vmax and intercept is 1/Vmax.
  for the case of inhibition, KM becomes KMapp and Vmax becomes Vmaxapp
  So a plot of 1/V vs 1/S is generated and the plot along with data points for both the absence and presence of inhibitorr are shown beow.
  
  when there is no inhibitor, the equation of bst fit gives 1/Vmax= intercept = 0.022, Vmax= 1/0.022 =45.45 umoles/min
  slope = KM/Vmax=0.224, Km= 0.224*45.45 uM=10.18 uM
  when there is inhibitor, 1/Vmaxapp= 0.112, Vmaxapp= 1/0.112= 8.93 umoles/min and Kmapp//Vmaxapp= 1.108
  Kmapp= 1.108* 8.93 uM=9.89 uM
  since Vmaxapp<Vmax, and Kmapp<Km, this inhibition is the case of mimics uncompetitive binding. in this type of inhibiton, the enzyme is capable enough to bind to the free enzyme and enzyme-substrate complex.
  for this inhibiton, 1/V= Km*(1+I/KI)/Vmax + (1+I/KI)/Vmax
  hence 1/ Vmaxapp = (1+I/KI)/Vmax
  1+I/KI= Vmax/Vmaxapp = 45.45/8.93=5.08, I/KI= 5.08-1=4.08
  KI= I/4.08= 100/4.08 uM=24.51 uM
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[zeph45]

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salamat po

 

[almonteeeeee]

Paunlock po salamat po.

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[Unkown User]

uestion: Ex. 1.13] A pump draws water from reservoir A and lifts it to reservoir B as shown in the figure....​

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  Premanand Gaikwadanswered this
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  Detailed answer of above asked question is solved as below.
  If any query/doubts, let me know in the comments box.
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[Unkown User]

 

[zeph45]

maraming maraming salamat po

 

[almonteeeeee]

Maraming salamat po!

 

[PH-Iskolar]

Pa-unlock po
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[Unkown User]

Question: B. 1.99 m D. 3.58 m 2. A central curve having a degree of 6 has a spiral curve 100 m long on two ...​

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Spiral Curves

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[hazardvio15]

pa help din po maraming salamat po

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