What's new

Pa help guys

m a e 0 9

Leecher
I'm really fond of even numbers, you know? That's why I'll be letting you make another even number problem yet again. This time, you need to print from a range of two inputted numbers, n1 and n2 (inclusive), all the even numbers from n2 down to n1, in descending order.
Input
1. Value of n1
Description
The first integer of the range
Constraints
The value of n1 is guaranteed to be lesser than or equal to n2.
Sample
3
2. Value of n2
Description
The second integer of the range
Constraints
The value of n2 is guaranteed to be greater than or equal to n1.
Sample
10
Output
The first line will contain a message prompt to input the value of n1. The second line will contain a message prompt to input the value of n2. The next line will contain all the even numbers from n2 down to n1.
Enter·value·of·n1:·3
Enter·value·of·n2:·10
10·8·6·4
 

FoXOnE23

Established
C++:
#include <iostream>
using namespace std;

int main()
{
    int n1=0, n2=0;
    cout<<"Enter the value of n1: ";
    cin>>n1;
    cout<<"Enter the value of n2: ";
    cin>>n2;
    while(n2>=n1)
    {
        if(n2%2==0)
        {
            cout<<n2<<" ";
        }
        n2 = n2 - 1;
    }
    return 0;
}

pwede rin to

C++:
#include <iostream>
using namespace std;

int main()
{
    int n1=0, n2=0;
    cout<<"Enter the value of n1: ";
    cin>>n1;
    cout<<"Enter the value of n2: ";
    cin>>n2;
    if(n2>=n1)
    {
        for(n2; n2>=n1; n2--)
        {
            if(n2%2==0)
            {
                cout<<n2<<" ";
            }
        }
    }
    return 0;
}
 
Last edited:

m a e 0 9

Leecher
C++:
#include <iostream>
using namespace std;

int main()
{
    int n1=0, n2=0;
    cout<<"Enter the value of n1: ";
    cin>>n1;
    cout<<"Enter the value of n2: ";
    cin>>n2;
    while(n2>=n1)
    {
        if(n2%2==0)
        {
            cout<<n2<<" ";
        }
        n2 = n2 - 1;
    }
    return 0;
}

pwede rin to

C++:
#include <iostream>
using namespace std;

int main()
{
    int n1=0, n2=0;
    cout<<"Enter the value of n1: ";
    cin>>n1;
    cout<<"Enter the value of n2: ";
    cin>>n2;
    if(n2>=n1)
    {
        for(n2; n2>=n1; n2--)
        {
            if(n2%2==0)
            {
                cout<<n2<<" ";
            }
        }
    }
    return 0;
}
paano po if c language?
 
Top