What's new
Pinoy Internet and Technology Forums
Take a moment to sign up and gain unlimited access and extra privileges that guests are not entitled to. Registration is quick, simple and absolutely free. Join our community today!

# HELP MGA MASTER! JAVA

Elite

#### PHC_Jayvee

##### .
Contributor
loop mo lang yan

loop You do not have permission to view the full content of this post. Log in or register now.

if even / odd You do not have permission to view the full content of this post. Log in or register now.

sa 2nd

loop lang din

tas gawa ka variable lowest and highest

tas sa highest

if number now is > number stored
--- set mo yung var to number now

same sa lowenst

#### Arcturus

Elite
Pa-test nalang din po, then paki check na din ng array.
Problem 1:
``````public class Main {
public static void main(String[] args) {
int[] field = {2, 20, 3, 13, 15, 3, 9, 10, 1, 5, 8};
int oddCount = 0;
for(int e : field)
if(e % 2 != 0)
oddCount++;
System.out.println("Odd Numbers Count: " + oddCount);
}
}``````

Last edited:

#### Arcturus

Elite
Problem 2:
``````public class Main {
public static void main(String[] args) {
int[] field = {2, 20, 3, 13, 15, 3, 9, 10, 1, 5, 8};
bubbleSort(field);
System.out.println("Max Number in Field " + field[field.length-1]);
System.out.println("Min Number in Field " + field[0]);
}

static int[] bubbleSort(int[] array){
for(int i = 0; i < array.length; i++){
for(int j = 0; j < array.length - 1; j++){
if(array[j] > array[j + 1]){
int temp = array[j];
array[j] = array[j + 1];
array[j + 1] = temp;
}
}
}
return array;
}
}``````

Replies
6
Views
186
Java Help
Replies
1
Views
143
Replies
2
Views
106
Replies
2
Views
124
Replies
0
Views
102

Members online
1,867
Guests online
1,288
Total visitors
3,155