What's new

Closed Create a program that accepts a number as an input. The program will then check an array if the value is inside or not.

Status
Not open for further replies.

Oh No_

Forum Veteran
Elite
Joined
Sep 29, 2016
Posts
2,515
Reaction
781
Points
905
You do not have permission to view the full content of this post. Log in or register now. <stdlib.h>
You do not have permission to view the full content of this post. Log in or register now.<stdio.h>
int main ()
{ srand(time(NULL));
int array[10];
for(int init=0;init<10; init++){
array[init] = (rand() % 20) + 1;
} printf("Array values: ");
for(int i=0;i<10; i++){
printf("%d ", array);
} printf("\n\n");
//your code here}



Example 1:
Array values: 2 4 1 3 4 12 16 10 9 18
Sorted: 1 2 3 4 4 9 10 12 16 18

Example 2:
Array values: 5 1 3 4 12 11 19 18 9 6
Sorted: 1 3 4 5 6 9 11 12 18 19


My coding:

#include <stdlib.h>
#include<stdio.h>

int main () {
srand(time(NULL));
int array[10];

for(int init=0;init<10; init++){
array[init] = (rand() % 20) + 1;
}
printf("Array values: ");
for(int i=0;i<10; i++){
printf("%d ", array);
}
printf("\n\n");

int i;

printf("Number to search for:");
scanf("%d",&array);

if(i<=array){
printf("Result: Number exists in array");
}else{
printf("Result: Number does not exist in array");
}
}
help me....
 
Last edited:
Status
Not open for further replies.

Similar threads

Back
Top