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Closed patulong php dev

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Dito

name="fullname"

yung fullname dapat ang gamitin mo sa post.

$fullname = $_POST['fullname'];
 
PHP:
$fullname = $_POST['fullname'];
$email = $_POST['email'];
$code = $_POST['password'];
$phone_number = $_POST['gender'];
$job = $_POST['job'];
$password = $_POST['password'];
$password = md5($password); //Password Encrypted

if (!empty ($fullname) || !empty($email) || !empty($code) || !empty($phone_number) || !empty($job) || !empty($password)) {
    $host = "localhost";
    $username = "root";
    $dbpassword = "";
    $dbname = "final_project";

//create connection here
    $conn= new mysqli($host,$username,$dbpassword,$dbname);
    if (mysqli_connect_error()) {
        die('Connect Error('.mysqli_connect_errno().')'.mysqli_connect_errno());
    }else{
        $SELECT = "SELECT email from register where email = ? Limit 1";
        $INSERT = "INSERT into register (fullname,email,code,phone_number,job,password) value(?,?,?,?,?,?)";

//Prepaired Statement

        $stmt = $conn->prepare($SELECT);
        $stmt->bind_param("s",$email);
        $stmt->execute();
        $stmt->bind_result($email);
        $stmt->store_result();
        $rnum = $stmt->num_rows;

        if ($rnum==0) {
            $stmt-> close();

            $stmt = $conn->prepare($INSERT);
            $stmt->bind_param("ssssii", $fullname,$email,$code,$phone_number,$job,$password);
            $stmt->execute();

            echo "Sign up Successfully!";

        }else{
            echo "Someone registered with this email";
        }
        $stmt->close();
        $conn->close();
    }

}else{
    echo "All field are required!";
    die();
}
?>


Copy mo na lang 'yan, kailangan mo gumawa ng form field para sa gender mo
 
PHP:
$stmt->bind_param("ssssii", $fullname,$email,$code,$phone_number,$job,$password);

nasa line na yan yung mali kaya ayaw mag save hanapin mo nlng
 
mali kasi yung:

$fullname = $_POST['name']

dapat kasi

$fullname= $_POST['fullname']


at yung:

$phone_number = $_POST['gender'] <---- bakit naging phone number yung gender mo?
change gender to $_POST['phone_number'] tapos create ka ulit ng form tas lagyan mo ng gender.

lastly,

$password = $_POST['pass'] to $password = $_POST['password']

yan lang naman error mo eh :)
 
Last edited:
dapat kasi same value yung ipapasok sa database table mo sa column nya para ma save yung output mo
 
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