SpectaculairE
Forum Guru
Ingat lang sa all caps heheheworking din paps!!!!
SUPER THANKS HAHAHA
THE BEST TALAGA PHC
Ingat lang sa all caps heheheworking din paps!!!!
SUPER THANKS HAHAHA
THE BEST TALAGA PHC
thanks for the info paps. appreciated muchKinulang ka lang po ng equals. Kung titingnan mo kung saan magfo-fall ang 5.5, makikita mo ’yung mali. Hindi siya pwede sa SOME DAMAGE o sa SERIOUS DAMAGE. Kaya nako-confuse ang entire program.
Hindi ba pwede nang ganito yan? bat pinapahaba mo pa?
#include <stdio.h>
int main()
{
float richterno;
printf("ENTER RICHTER NUMBER: ");
scanf("%f",&richterno);
if (richterno < 5)
{
printf("LITTLE OR NO DAMAGE \n");
}
else if (richterno >=5)
{
printf("SOME DAMAGE \n");
}
else if (richterno >=5.5 )
{
printf("SERIOUS DAMAGE \n");
}
else if (richterno >= 6.5)
{
printf("DISASTER \n");
}
else
{
printf("CATASTROPHE \n");
}
return 0;
}
else if (richter >= 5)
mali ang pag codeHindi ba pwede nang ganito yan? bat pinapahaba mo pa?
#include <stdio.h>
int main()
{
float richterno;
printf("ENTER RICHTER NUMBER: ");
scanf("%f",&richterno);
if (richterno < 5)
{
printf("LITTLE OR NO DAMAGE \n");
}
else if (richterno >=5)
{
printf("SOME DAMAGE \n");
}
else if (richterno >=5.5 )
{
printf("SERIOUS DAMAGE \n");
}
else if (richterno >= 6.5)
{
printf("DISASTER \n");
}
else
{
printf("CATASTROPHE \n");
}
return 0;
}
Hi mga paps, I am new at c laguage, pahelp naman po kung anong mali dito sa ginawa koooo, hahahah I can't seem to find where did I mistaken
View attachment 656820
Matapos ko syang i-compile and run, once na nag input ako ng number di nya binabasa yung sumunod na if else statement, hanggang dun lang sya sa "SOME DAMAGE"
pa help naman po jan sa mga experts or my knowledge about c language
Thanks in advance mga paps
if (richterno >= 7.5)
printf("CATASTROPHY \n");
if (richterno >= 6.5 && richterno <= 7.4)
printf("DISASTER \n");
if (richterno >=5.5 && richterno <= 6.4)
printf("SERIOUS DAMAGE \n");
if (richterno >=5 && richterno <= 5.4)
printf("SOME DAMAGE \n");
if (richterno < 5)
printf("LITTLE OR NO DAMAGE \n");
Hindi ba pwede nang ganito yan? bat pinapahaba mo pa?
#include <stdio.h>
int main()
{
float richterno;
printf("ENTER RICHTER NUMBER: ");
scanf("%f",&richterno);
if (richterno < 5)
{
printf("LITTLE OR NO DAMAGE \n");
}
else if (richterno >=5)
{
printf("SOME DAMAGE \n");
}
else if (richterno >=5.5 )
{
printf("SERIOUS DAMAGE \n");
}
else if (richterno >= 6.5)
{
printf("DISASTER \n");
}
else
{
printf("CATASTROPHE \n");
}
return 0;
}
#include <stdio.h>
int main(int argc, char* argv[]) {
float r;
printf("ENTER RICHTER NUMBER: ");
scanf("%f", &r);
printf("You entered: %f\n", r);
if (r<5.000000) {
printf("LITTLE TO NO DAMAGE\n");
}
else if (r>=5.000000 && r<5.600000) {
printf("SOME DAMAGE\n");
}
else if (r>=5.600000 && r<=6.500000) {
printf("SERIOUS DAMAGE\n");
}
else if (r>=6.600000 && r<=7.500000) {
printf("DISASTER\n");
}
else {
printf("CATASTROPHE\n");
}
}
Actually, kung walang pre-processing ng input galing sa scanf, the value contains a precision of 6 decimal places (ie, 5.000000) such that it won't match any of your original if-else conditions. This one should work:
Code:#include <stdio.h> int main(int argc, char* argv[]) { float r; printf("ENTER RICHTER NUMBER: "); scanf("%f", &r); printf("You entered: %f\n", r); if (r<5.000000) { printf("LITTLE TO NO DAMAGE\n"); } else if (r>=5.000000 && r<5.600000) { printf("SOME DAMAGE\n"); } else if (r>=5.600000 && r<=6.500000) { printf("SERIOUS DAMAGE\n"); } else if (r>=6.600000 && r<=7.500000) { printf("DISASTER\n"); } else { printf("CATASTROPHE\n"); } }
Pero kung gusto mo lang ng 2-decimal places (which makes a lot of sense), pre-process the input prior to testing.